Q#3 :The following are the results of
different tests on soil samples are provided in the following table.
Soil sample
|
Percent
passing sieve
|
Liquid Limit
|
plasticity
Index
|
No 10
|
No 40
|
No 200
|
A
|
100
|
75
|
25
|
35
|
15
|
B
|
100
|
85
|
30
|
45
|
22
|
C
|
80
|
45
|
10
|
25
|
12
|
Classify
the soil according to AASTHO classification and determine the Group Index in
each case. You may use the information provided.
ANSWER
SOIL Sample A
Percentage
passing through No. 10 (2mm) seive = 100%
Percntage
passing through No. 40 (425 μm) seive = 75%
Percentage
passing through No. 200 (75 μm) seive
= 25%
Liquid
limit = wL = 35
Plasticity index = Ip = 15
Percenrage passing through no. 200 seieve < 35%
So there for
soil is granual
because Percentage passing through no.10 (2mm) seive >
50%
Percentage passing through no. 40 (425 μm) seive > 50%
Percentage passing through no.200(75 μm) >10%
< 35%
There fore soil group is A -2
Because wL < 40
and Ip > 11
There fore soil subgroup is A-2-6
Group index of the
soil is given as
GI = 0.2a = 0.005ac +0.01 bd
a = percentage passing through 75 μm
seive -35 a ≤ 40
b = percentage passing through 75 μm seive
-15 b ≤ 40
c = wL -40
c ≤ 20
d = Ip– 10
d ≤ 20
Therefore,
a= 25-35= -10
b =25-15 =10
c = 35-40 = -5
d = 15-10 = 5
GI= 0.2 × (-10)+0.005 ×(-10)(-5)+0.01 × (10)(5)
GI = -2+0.25+0.5
GI = -1.5
There is no negative group index of soil is zero
There for soil
classified is A-2-6
SOIL Sample B
Percentage
passing through No. 10 (2mm) seive = 100%
Percntage
passing through No. 40 (425 μm)
seive = 85%
Percentage
passing through No. 200 (75 μm) seive = 30% (My reg no.)
Liquid
limit = wL = 45
Plasticity
index = Ip = 22
Percenrage passing through no. 200 seieve >35%
So there for
soil is silt clay type
because wL >
41 and Ip >
11
There fore soil
group is A -7
(wL - 30) = 45 -30
=15
Because and
Ip > (wL - 30)
There fore soil
subgroup is A-7-6
Group index of the
soil is given as
GI = 0.2a = 0.005ac +0.01 bd
a = percentage passing through 75 μm
seive -35 a ≤ 40
b = percentage passing through 75 μm seive
-15 b ≤ 40
c = wL -40
c ≤ 20
d = Ip– 10
d ≤ 20
Therefore,
a= 30-35=-5
b =30-15 =15
c = 45-40 = 5
d = 22-10 = 12
GI= 0.2 × (-5) +0.005 × (-5) ×5 +0.01 × 15 ×12
GI = 0.675
The group index of soil is = 0.675
There for soil
classified is A-7-6(0.675) (clay
soil)
SOIL Sample C
Percentage
passing through No. 10 (2mm) seive = 80%
Percntage
passing through No. 40 (425 μm) seive = 45%
Percentage
passing through No. 75 (75 μm) seive
= 10%
Liquid
limit = wL = 25
Plasticity index = Ip = 12
Percentage passing through no. 200 seieve < 35%
So there for
soil is granual
because Percentage passing through no.10 (2mm) seive >
50%
Percentage passing through no. 40 (425 μm) seive < 50%
Percentage passing through no.200(75 μm) >10%
< 25%
There fore soil
subgroup is A-2-6
Group index of the soil is given as
GI = 0.2a = 0.005ac +0.01 bd
a = percentage passing through 75 μm
seive -35 a ≤ 40
b = percentage passing through 75 μm seive
-15 b ≤ 40
c = wL -40
c ≤ 20
d = Ip– 10
d ≤ 20
Therefore,
a= 10-35= - 25
b =10-15 = -5
c = 25-40 = 15
d = 12-10 = 2
GI= 0.2 × (-25)+0.005 ×(-25)(-15)+0.01 × (-5)(2)
GI = -5+1.875+0.01
GI = -3.135
There for group index of soil is zero
There for soil
classified is A-1-b(0)