A horizontal venturimeter with inlet diameter 20cm and throat dia 10cm is used to measure the flow of oil of specific gravity 0.8. The discharge of the oil through venturimeter is 60 lit/sec. Find the reading of the oil-Hg differential manometer, take Cd= 0.98.
Solution:
At entry, d1=20cm
a1= (π/4)*202 = 314.16 cm2
At throat, d2 = 10cm
a2 = (π/4)*102 = 78.54 cm2
Cd = 0.98
Q = 60 lit/sec= 60*1000 cm3 /sec
Q = Cd[a1a2 /√( a1 2 - a2 2 )]* √(2gh)
60*1000 = 0.98[314.16*78.54/√( 314.162 -78.542 )]*√(2*9.81*h)
√h= 17.029, h= 289.98 cm of oil
To calculate reading of the oil-Hg differential manometer
we have
h =x[(sh/sp)-1]
Where sh = 13.6 –> sp. gravity of the mercury
sp = 0.8 --> sp. gravity of the oil
x = ?
x= 18.12 cm
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