A pipe 200m long slopes down at 1 in 100
and tapers from 600mm diameter at the higher end to 300mm diameter at the lower
end, and carries 100 lit/sec of oil (specific gravity 0.8). If the pressure
gauge at the higher end reads 60 kN/m2 . Determine,
i. Velocities at both ends.
ii. Pressure at the lower end. Neglect the
losses
Solution:
Given: Length of the pipe, l= 200mm
Diameter of the pipe at the higher end,
D1 =600mm= 0.6m, Area, A1 = (π/4)*0.62
=0.283 m2
Diameter of the pipe at the lower end,
D2 =300mm= 0.3m, Area, A2 = (π/4)*0.32 =
0.0707 m2
Height of the lower end, above datum Z2
=0
Rate of oil flow, Q=100lit/sec= 0.1 m3
/sec
Pressure at the higher end, p1 =60kN/m2
(i)
Velocities, V1 & V2
Now Q=A1V1 = A2V2
Where V1 & V2 are the velocities at
the higher and lower side respectively.
V1= Q/A1 =0.1/0.283= 0.353m/sec
V2= Q/A2=0.1/0.0707=1.414m/sec, and
(ii) Pressure at the lower end, p2
Using Bernoulli’s equation for both ends
of pipe, we have
p1/w+v1 2 /2g+z1=p2/w+v2 2 /2g+z2
60/(0.8*9.81)+0.3532
/(2*9.81)+2=p2/(0.8*9.81)+(1.4142 /2*9.81)+0
p2 /(0.8*9.81) = 9.54,
Pressure at lower end, p2 = 74.8 kN/m2
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