A pipe conveys 0.25 kg/sec of air at 300K under an absolute pressure of 2.25bar. Calculate minimum diameter of the pipe required if the fluid velocity is limited to 7.5 m/sec.
Solution:
Density of air ρ= P/RT= (2.25*105 )/(287*300)= 2.61kg/m3
Mass flow of air, m = ρAV 0.25
=2.61*A*7.5
Min. area (A) = (0.25*1) / (2.61*7.5) = 0.01277 m 2
Min. dia. =√(0.01277*4)/π = 0.1275m
= 12.75 mm
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