Determine the magnitude of the resultant force by adding the rectangular components of the three forces.
Solution:
First, we must add/ sum up all the forces for x-components. That is...
Fx(Rx)= F1x + F2x + F3x (since F3 is parallel to y-axis,F3x=0)
= -50cos30 + 75cos45 + 50cos90
Fx(Rx)= 9.7317...N
Then, add/sum up all the forces for y-components.
Fy(Ry)= F1y + F2y + F3y
= 50sin30 + 75sin45 - 50sin90
Fy(Ry)= 28.03300...N
R=*squareroot of [(Ry)^2 + (Rx)^2]
=*suareroot of [(28.03300859 N)^2 + (9.7317384 N)^2]
R=29.67416895 N
θ= arctan [Ry/Rx]
= arctan [28.03300859/9.7317384]
θ= 70.86 degrees
Therefore, the answer is 29.67416895 N
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