The ball joint is subjected to the three forces shown. Find the magnitude of the resultant force.
Solution
for
F1X = 1.25 (since f1 is parallel to x- axis)F2y = 5(sin 30) = 2.5
F2z = 5(cos 30) = 4.330
F3y = 2(3/5) = 1.2
F3z = 2(4/5) = 1.6
summation along x = 1.25 = 1.25
summation along y = -2.5 + 1.2 = -1.3
summatiob along z = 4.330+1.6 = 5.93
R = SQUARE ROOT OF (fx+fy+fz)
R = SQUARE ROOT OF ((1.25)square)+ ((-1.3)square + ((5.93)square)
R = 6.20 KN
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