Saturday, August 21, 2021

There are multiple data sources on the subject you are currently studying - weights of students in college. You’re interested in data that has low variability and a large sample size, the problem is that the data you found isn’t in kilograms but in pounds. Using variance and standard deviation in pounds (1 kg = 2.20462 lb), which data set out of the following would you choose? Measure Data Set A Data Set B Data Set C Sample Size 15 670 4 500 9 334 Mean 550 464 534 Standard Deviation 432 140 210

 Problem    There are multiple data sources on the subject you are currently studying - weights of students in college. You’re interested in data that has low variability and a large sample size, the problem is that the data you found isn’t in kilograms but in pounds. Using variance and standard deviation in pounds (1 kg = 2.20462 lb), which data set out of the following would you choose?

MeasureData Set AData Set BData Set C
Sample Size15 6704 5009 334
Mean550464534
Standard Deviation432140210

 Solution 

Here, you were asked to:

  • Convert the variance and SD to pounds using the conversion 1 kg = 2.20462 lb
  • Choose a data set with low variability and a large sample size

To convert the variance and SD, we simply need to follow the rules for changing units, as seen in the table below.

MeasureData Set AData Set BData Set C
Sample Size15 6704 5009 334
Mean

  \[ \dfrac{550}{2.2} = 250 \]

  \[ \dfrac{464}{2.2} = 211 \]

  \[ \dfrac{534}{2.2} = 243 \]

Standard Deviation

  \[ \dfrac{432}{2.2} = 196 \]

  \[ \dfrac{140}{2.2} = 64 \]

  \[ \dfrac{210}{2.2} = 95 \]

CV79%30%39%

To find a preferred data set, you can use the coefficient of variation. Recall that the formula is,

[\

CV = \frac{s}{\bar{x}} *100%

\]

Which tells us the proportion of the standard deviation to the mean. This is what appears in the last row of the table. Because Data Set C has the second lowest variability but almost double the sample size of Data Set B, we’ll choose Data Set C.

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