b.
Machines A, B and C make resistors 1, 2 and 3 respectively. The
acceptability of the three resistors are 90%, 93% and 81% respectively. Three
resistors arepicked at random sampling with replacement. Find the probability
that
i.
All
resistors are acceptable.
ii.
P(A) = 0.9
iii.
P(B) = 0.93
iv.
P(C) = 0.81
Since
A , B and C are the independent events, therefore
P(AՌBՌC)
= P(A) P(B) P(C)
= 0.9 * 0.93 * 0.81
= 0.678
= 67.8% Answer
v.
All
resistors are not acceptable.
P(all
resistors are not acceptable) = 1
- P(all resistors are acceptable)
= 1 – 0.678
= 0.322
= 32.2% Answer
vi.
At
least one resistor is acceptable. [Marks-01]
P(At least one resistor is acceptable) =
P(AUBUC)
P(AUBUC)
= P(A) +P(B) +P(C) -P(AՌB)-P(BՌC) –
P(AՌC) + P(AՌBՌC)
= 0.9 + 0.93 +0.81 – 0.9*0.93 – 0.93*0.81 –
0.9*0.81 + 0.678
= 0.998
= 99.8% Answer
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