A simply supported beam, 8 m long, carries a uniformly distributed load of 10 kN/m over the entire span. Find: Reactions at supports Maximum bending moment

 A simply supported beam, 8 m long, carries a uniformly distributed load of 10 kN/m over the entire span. Find:

1. Reactions at supports

2. Maximum bending moment

Solution:

• Reaction at supports: $R_A = R_B = \frac{wL}{2} = \frac{10 \cdot 8}{2} = 40 \text{ kN}$

• Max bending moment (midspan): $M_{max} = \frac{wL^2}{8} = \frac{10 \cdot 8^2}{8} = 80 \text{ kNm}$

Answer:

• Reactions: 40 kN each

• Max bending moment: 80 kNm