A horizontal venturimeter with inlet diameter 20cm and throat diameter 10cm is used to measure the flow of water. The pressure at inlet is 17.658 N/cm2 and the vacuum pressure at the throat is 30cm of mercury. Find the discharge of water through venturimeter. Take Cd=0.98
Solution:
Dia at inlet, d1=20cm
a1=(πd1 2 )/4=(π202 )/4=314.16cm2
Dia at throat,d2=10cm a
2=(π102 )/4=78.54cm2
p1=17.658 N/cm2 =17.658*104N/m2
density of water = 1000kg/m3 and
Therefore, p1/ρg=17.658*104 /9.81*1000=18m of water
p2/ρg= -30cm of mercury (vacuum pr. Head)
= - 0.30m of mercury
= - 0.30*13.6
= - 4.08 m of water
Therefore differential head
h= p1/ρg - p2/ρg =18-(-4.08)
= 18+4.08=22.08 m of water = 2208 cm of water
The discharge Q is given by equation
Q= Cd*(a1a2/(√a1 2 -a2 2 ))*(√2gh)
=0.98*(314.16*78.54/(√314.162 78.542 ))*(√2*9.81*2208)
=50328837.21/304
=1655555 cm3 /s
Q =165.55 lit/s
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