A venturimeter has its axis vertical , the inlet & throat diameter being 150mm & 75mm respectively. The throat is 225mm above inlet and Cd = 0.96. Petrol of specific gravity 0.78 flows up through the meter at a rate of 0.029 m3 /sec. find the pressure difference between the inlet and throat.
Solution:
The discharge through a venturimeter is given by
Q = Cd [a1a2 /√( a1 2 - a2 2 )]* √(2gh)
Given:
Cd = 0.96
d1 =150mm= 0.015m
d2 =75mm= 0.0075m
a1 =(π/4)*0.0152 =0.0177m2
a2 =(π/4)*0.00752 =0.0044m2
Q = 0.029 m3 /sec
By substitution, we have
0.029 = 0.96[0.0177*0.0044 /√( 0.01772 - 0.00442 )]*√(2*9.81*h)
h= 2.254m of oil
h= (p1/w+z1) - (p2/w + z2)
2.254= [(p1/w)- (p2/w)]-[ z2-z1]
2.254= [(p1/w)- (p2/w)]-[0.225]
p1/ρg - p2/ρg =2.479
Therefore, p1 - p2= 2.479*0.78*9810 = 18969 N/m2
=18.969k N/m2 =18969 Pa
Pr. Difference, p1 - p2 = 18.96 kPa
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