Calculate
charles's law/Gay's' law for Pressure/volume and temperature
solution
The
particle theory of gas pressure was explained in Part 1 so this section concentrates on the gas
law calculations involving pressure and volume and their variation with
temperature.
- Charles's/Gay–Lussac's
Law states
that for a fixed mass of gas ...
§ V = constant x T (right graph), or
§ V/T = constant, or
§ V1/V2 =
T1/T2
for conditions changing from 1 (initial) to 2 (final),
§ or V1/T1 = V2/T2
for constant pressure
§ V1 x
T2 = V2 x T1
§ V2 =
V1 x T2/T1
§ or T2 = T1 x V2/V1
§ Kinetic particle reasoning - increasing the
temperature increases the kinetic energy of the molecules giving more forceful
collisions which push out (expand) the gas at constant pressure.
§ Note that the graphs extrapolate back to 0K (absolute
zero, Kelvin scale) or -273oC (Celsius
scale).
§ p = constant x
T (right graph),
or
§ p/T = constant, or
§ p1/p2 =
T1/T2 for conditions
changing from 1 (initial) to 2 (final),
§ or p1/T1 = p2/T2
for constant volume
§ p1 x T2 = T1 x p2
§ p2 =
p1 x T2/T1
§ or T2 = T1 x p2/p1
§ Kinetic particle reasoning - increasing the
temperature increases the kinetic energy of the molecules giving more forceful
collisions that increase the pressure if the volume is constrained (kept constant).
§ Note again that the graphs extrapolate back to 0K (absolute
zero, Kelvin scale) or -273oC (Celsius
scale).
- In all calculations, the absolute or Kelvin scale of
temperature must be used for T (K = oC + 273).
- If all the laws described in 4a and 4b are combined,
you get the following general expression
- p x V/T = a constant (for a given mass of gas).
- This can be expressed in generalised form for
calculations based on an initial set of conditions1 (1) changing to a new and final
set of conditions2 (2)
for a given mass of gas, giving the combined pressure–volume–temperature
gas calculation equation ...
p1 x V1 |
p2 x V2 |
|
–––––––––––– |
= |
–––––––––––– |
T1 |
T2 |
- In shorthand': p1V1 /T 1 =
p2V2 / T2
- therefore the three
permutations for problem solving involving all three variables are:
- p2 = p1V1T2 /
V2T1
- V2 = p1V1T2 /
p2T1
- T2 = p2V2T1 /
p1V1
- If one variable is constant,
the permutations for the other two variables are:
- p2 = p1V1 /
V2 (at constant
temperature)
- V2 = V1T2 /
T1 (at constant
pressure)
- T2 = p2T1 /
p1 (at constant
volume)
- Note:
- If the temperature is constant you get Boyle's Law.
- If p or V is constant you get Charles's/Gay–Lussac's
Law.
- You can use any volume or pressure units you like as
long as both p's or both V's have the same units.
- The graphs of p or V versus temperature become invalid
once the gas has condensed into a liquid BUT when extrapolated back all
the lines seem to originate from y = 0 (for p or V), x = –273oC
(for T).
- This was part of the scientific evidence that led to
the belief that –273oC was the lowest possible temperature,
though there is no theoretical upper limit at all.
- This led to the devising of a new thermodynamic
absolute temperature scale or Kelvin scale which starts at OK.
§ e.g. ice melts at 0oC or 273K and
water boils at 100oC or 373K.
No comments:
Post a Comment