The fuel and air gases in the cylinders of a
1200 cm3 car engine go from 25oC before combustion
and rise to a peak temperature of 2100oC after combustion. If normal
atmospheric pressure is 101kPa, calculate the peak pressure reached after
combustion. Although the movement of the piston changes the volume, (i) for the
sake of argument assume the volume is constant.
·
T1 = 25 + 273 = 298 K, T2 =
2100 + 273 = 2373 K, P1 = 101 KPa
·
p/T = constant
·
p1/p2 = T1/T2
·
p2 = p1 x T2/T1
·
p2 = 101 x 2373/298 = 804 kPa
o (ii)
To be more realistic, assume the initial volume of fuel vapour plus air was 400
cm3, now re-calculate the final pressure.
o You
now need to use the full PVT expression.
o (p1 x
V1)/T1 = (p2 x V2)/T2
o p2 = (p1 x
V1 x T2)/(V2 x T1)
o p2 = (101
x 400 x 2373)/(1200 x 298) = 268
kPa
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