Thursday, August 12, 2021

How does the equation WL^2/8 get in a simply supported beam subject to UDL?

How does the equation WL^2/8 get in a simply supported beam subject to UDL?

 You can refer this Pictures…….

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Considering a section At a distance x from A and finding the Bending Moment at X. Then substituting x=l/2 in that equation (as max BM occurs in Center) to get the BM at Center……Simply….

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